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This is what I did:

Force up - Fg = ma

1.2N - 1N = .1kg a

a = 2m/s^2 upward

I used this info to calculate the speed right before the explosion:

V = Vi + at

V = 0 + 2m/s^2 * 5s= 10m/s

The distance elapsed in this time is:

Y = Vi*t + 1/2gt^2

Y = 1/2 (2m/s^2)*(5s)^2 = 25m

Since the problem says after the 5s the cracker explodes, I thought the fragment that goes left takes 5s to come back down and the distance it would travel is 75m. But I'm wrong. It travels 33m.

X = Vi*t + 0

The fragment moving to the right is at an angle so it has a horizontal and vertical components. Vx is 15m/s and Vy is 20m/s.

Can someone guide me please? Thanks